7.8

CVE-2026-31473

media: mc, v4l2: serialize REINIT and REQBUFS with req_queue_mutex

In the Linux kernel, the following vulnerability has been resolved:

media: mc, v4l2: serialize REINIT and REQBUFS with req_queue_mutex

MEDIA_REQUEST_IOC_REINIT can run concurrently with VIDIOC_REQBUFS(0)
queue teardown paths. This can race request object cleanup against vb2
queue cancellation and lead to use-after-free reports.

We already serialize request queueing against STREAMON/OFF with
req_queue_mutex. Extend that serialization to REQBUFS, and also take
the same mutex in media_request_ioctl_reinit() so REINIT is in the
same exclusion domain.

This keeps request cleanup and queue cancellation from running in
parallel for request-capable devices.
Daten sind bereitgestellt durch National Vulnerability Database (NVD)
Linux ≫ Linux Kernel Version >= 4.20.1 < 5.10.253
Linux ≫ Linux Kernel Version >= 5.11 < 5.15.203
Linux ≫ Linux Kernel Version >= 5.16 < 6.1.168
Linux ≫ Linux Kernel Version >= 6.2 < 6.6.131
Linux ≫ Linux Kernel Version >= 6.7 < 6.12.80
Linux ≫ Linux Kernel Version >= 6.13 < 6.18.21
Linux ≫ Linux Kernel Version >= 6.19 < 6.19.11
Linux ≫ Linux Kernel Version4.20 Update-
Linux ≫ Linux Kernel Version7.0 Updaterc1
Linux ≫ Linux Kernel Version7.0 Updaterc2
Linux ≫ Linux Kernel Version7.0 Updaterc3
Linux ≫ Linux Kernel Version7.0 Updaterc4
Linux ≫ Linux Kernel Version7.0 Updaterc5
Linux ≫ Linux Kernel Version7.0 Updaterc6
Linux ≫ Linux Kernel Version7.0 Updaterc7
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EPSS Metriken
Typ Quelle Score Percentile
EPSS FIRST.org 0.01% 0.024
CVSS Metriken
Quelle Base Score Exploit Score Impact Score Vector String
416baaa9-dc9f-4396-8d5f-8c081fb06d67 7.8 1.8 5.9
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
CWE-416 Use After Free

The product reuses or references memory after it has been freed. At some point afterward, the memory may be allocated again and saved in another pointer, while the original pointer references a location somewhere within the new allocation. Any operations using the original pointer are no longer valid because the memory "belongs" to the code that operates on the new pointer.