7.8
CVE-2025-22126
- EPSS 0.02%
- Veröffentlicht 16.04.2025 14:13:09
- Zuletzt bearbeitet 03.11.2025 20:17:44
- Quelle 416baaa9-dc9f-4396-8d5f-8c081f
- CVE-Watchlists
- Unerledigt
In the Linux kernel, the following vulnerability has been resolved:
md: fix mddev uaf while iterating all_mddevs list
While iterating all_mddevs list from md_notify_reboot() and md_exit(),
list_for_each_entry_safe is used, and this can race with deletint the
next mddev, causing UAF:
t1:
spin_lock
//list_for_each_entry_safe(mddev, n, ...)
mddev_get(mddev1)
// assume mddev2 is the next entry
spin_unlock
t2:
//remove mddev2
...
mddev_free
spin_lock
list_del
spin_unlock
kfree(mddev2)
mddev_put(mddev1)
spin_lock
//continue dereference mddev2->all_mddevs
The old helper for_each_mddev() actually grab the reference of mddev2
while holding the lock, to prevent from being freed. This problem can be
fixed the same way, however, the code will be complex.
Hence switch to use list_for_each_entry, in this case mddev_put() can free
the mddev1 and it's not safe as well. Refer to md_seq_show(), also factor
out a helper mddev_put_locked() to fix this problem.Verknüpft mit AI von unstrukturierten Daten zu bestehenden CPE der NVD
Daten sind bereitgestellt durch National Vulnerability Database (NVD)
Linux ≫ Linux Kernel Version >= 6.0 < 6.1.135
Linux ≫ Linux Kernel Version >= 6.2 < 6.6.88
Linux ≫ Linux Kernel Version >= 6.7 < 6.12.25
Linux ≫ Linux Kernel Version >= 6.13 < 6.14.2
| Typ | Quelle | Score | Percentile |
|---|---|---|---|
| EPSS | FIRST.org | 0.02% | 0.031 |
| Quelle | Base Score | Exploit Score | Impact Score | Vector String |
|---|---|---|---|---|
| nvd@nist.gov | 7.8 | 1.8 | 5.9 |
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
|
CWE-416 Use After Free
The product reuses or references memory after it has been freed. At some point afterward, the memory may be allocated again and saved in another pointer, while the original pointer references a location somewhere within the new allocation. Any operations using the original pointer are no longer valid because the memory "belongs" to the code that operates on the new pointer.