7.8

CVE-2024-26616

In the Linux kernel, the following vulnerability has been resolved:

btrfs: scrub: avoid use-after-free when chunk length is not 64K aligned

[BUG]
There is a bug report that, on a ext4-converted btrfs, scrub leads to
various problems, including:

- "unable to find chunk map" errors
  BTRFS info (device vdb): scrub: started on devid 1
  BTRFS critical (device vdb): unable to find chunk map for logical 2214744064 length 4096
  BTRFS critical (device vdb): unable to find chunk map for logical 2214744064 length 45056

  This would lead to unrepariable errors.

- Use-after-free KASAN reports:
  ==================================================================
  BUG: KASAN: slab-use-after-free in __blk_rq_map_sg+0x18f/0x7c0
  Read of size 8 at addr ffff8881013c9040 by task btrfs/909
  CPU: 0 PID: 909 Comm: btrfs Not tainted 6.7.0-x64v3-dbg #11 c50636e9419a8354555555245df535e380563b2b
  Hardware name: QEMU Standard PC (Q35 + ICH9, 2009), BIOS 2023.11-2 12/24/2023
  Call Trace:
   <TASK>
   dump_stack_lvl+0x43/0x60
   print_report+0xcf/0x640
   kasan_report+0xa6/0xd0
   __blk_rq_map_sg+0x18f/0x7c0
   virtblk_prep_rq.isra.0+0x215/0x6a0 [virtio_blk 19a65eeee9ae6fcf02edfad39bb9ddee07dcdaff]
   virtio_queue_rqs+0xc4/0x310 [virtio_blk 19a65eeee9ae6fcf02edfad39bb9ddee07dcdaff]
   blk_mq_flush_plug_list.part.0+0x780/0x860
   __blk_flush_plug+0x1ba/0x220
   blk_finish_plug+0x3b/0x60
   submit_initial_group_read+0x10a/0x290 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   flush_scrub_stripes+0x38e/0x430 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   scrub_stripe+0x82a/0xae0 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   scrub_chunk+0x178/0x200 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   scrub_enumerate_chunks+0x4bc/0xa30 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   btrfs_scrub_dev+0x398/0x810 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   btrfs_ioctl+0x4b9/0x3020 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965]
   __x64_sys_ioctl+0xbd/0x100
   do_syscall_64+0x5d/0xe0
   entry_SYSCALL_64_after_hwframe+0x63/0x6b
  RIP: 0033:0x7f47e5e0952b

- Crash, mostly due to above use-after-free

[CAUSE]
The converted fs has the following data chunk layout:

    item 2 key (FIRST_CHUNK_TREE CHUNK_ITEM 2214658048) itemoff 16025 itemsize 80
        length 86016 owner 2 stripe_len 65536 type DATA|single

For above logical bytenr 2214744064, it's at the chunk end
(2214658048 + 86016 = 2214744064).

This means btrfs_submit_bio() would split the bio, and trigger endio
function for both of the two halves.

However scrub_submit_initial_read() would only expect the endio function
to be called once, not any more.
This means the first endio function would already free the bbio::bio,
leaving the bvec freed, thus the 2nd endio call would lead to
use-after-free.

[FIX]
- Make sure scrub_read_endio() only updates bits in its range
  Since we may read less than 64K at the end of the chunk, we should not
  touch the bits beyond chunk boundary.

- Make sure scrub_submit_initial_read() only to read the chunk range
  This is done by calculating the real number of sectors we need to
  read, and add sector-by-sector to the bio.

Thankfully the scrub read repair path won't need extra fixes:

- scrub_stripe_submit_repair_read()
  With above fixes, we won't update error bit for range beyond chunk,
  thus scrub_stripe_submit_repair_read() should never submit any read
  beyond the chunk.
Daten sind bereitgestellt durch National Vulnerability Database (NVD)
LinuxLinux Kernel Version >= 6.4 < 6.6.15
LinuxLinux Kernel Version >= 6.7 < 6.7.3
LinuxLinux Kernel Version6.8 Updaterc1
Zu dieser CVE wurde keine CISA KEV oder CERT.AT-Warnung gefunden.
EPSS Metriken
Typ Quelle Score Percentile
EPSS FIRST.org 0.02% 0.021
CVSS Metriken
Quelle Base Score Exploit Score Impact Score Vector String
nvd@nist.gov 7.8 1.8 5.9
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
CWE-416 Use After Free

The product reuses or references memory after it has been freed. At some point afterward, the memory may be allocated again and saved in another pointer, while the original pointer references a location somewhere within the new allocation. Any operations using the original pointer are no longer valid because the memory "belongs" to the code that operates on the new pointer.